Correct answer: Ra71...a3[a] 2.Rc4#[A] 1.Rc2? zz 1...a3[a] 2.Rc4#[A] 1...Ka3[c] 2.Qd6#[Б] but 1...b5/[б]/! 1.Qe5? zz 1...a3[a] 2.Rc4#[A] 1...b5/[б]/ 2.Qc3#[C] b