Correct answer: Qh51...K:d5[a] 2.Qa8#[A] 1...e:d5/[б]/ 2.Qg6#[Б] 1.Qf7? zz 1...K:d5[a] 2.Qb7#[C] 1...e:d5/[б]/ 2.Qg6#[Б] but 1...Kf5! 1.Qa4? zz 1...K:d
