Correct answer: d71...Re4[a]/Re3[a]/Re2[a]/Re1[a]/Re6/[б]//Re7[a]/Re8[a]/Bb7/Ba6[a] 2.R:f5#[A] 1...Qf2/Qf3/Q:g2[c]/Qc4[c] 2.Qc4#[Б] 1...Q<