Correct answer: Qg51...f4[a] 2.Be4#[A] 1...e4/[б]/ 2.Rd4#[Б] 1...Bh7/Be6 2.Qe6# 1.B:e5?? (2.Rd4#[Б]) but 1...B:f6! 1.Q:f5?? (2.Rd4#[Б]/Qd3#) 1...K