Correct answer: B:e21.Be6[A]? (2.N:e2#[Б]/N:b3#[C]/N:b5#[D]) 1...N:e6[a] 2.N:e6#[E] 1...e1Q/e1R/e1B/e1N 2.Ne2#[Б] 1...b:c2 2.Nb3#[C] but 1...g5!