Correct answer: Rf1+1.Ra4? (2.Qg4#[A]) but 1...Ke6[a]! 1.Ra6? (2.Qg6#[Б]) but 1...Ke4/[б]/! 1.Rd1? zz 1...Ke6[a] 2.Qg6#[Б] 1...Ke4/[б]/ 2.Qg4#[A] b