Correct answer: Qe11...g5[a] 2.Qe8#[A] 1.Qe4? (2.Qg4#[Б]/Qh4#[C]) 1...g5[a] 2.Qe8#[A] 1...Bg5/[б]/ 2.Qg4#[Б]/Qf3#[D] 1...Kg5 2.Qe5# but 1...Bf4! 1
