Correct answer: Qd71.Bd4? zz 1...B:b5[a] 2.Q:e6#[A] 1...B:c5/[б]/ 2.Q:c5#[Б] but 1...e5! 1.Qd6? zz 1...B:b5[a] 2.Qd4#[D] 1...B:c5/[б]/ 2.Qd3#[C] but 1.
