Correct answer: Nd31...Qb2[a]/Qb3/[б]//Qb4[c]/Qb5[d]/Qh1[g] 2.Q:f5#[A] 1...Q:a1/Qc1/Qd1[e]/Qe1/Qg1[e]/Qa2 2.R:b6#[Б]/Q:f5#[A] 1...Qf1[f]/Q