Correct answer: d71...Bc6[a] 2.Rd4#[A] 1...B:e5/[б]/ 2.Nb4#[Б] 1.Kd7? (2.Rd4#[A]) 1...B:e5/[б]/ 2.Nb4#[Б] but 1...Bc6+[a]! 1.Kf6? (2.Nb4#[Б]) 1...