Correct answer: Rc71...Kd6[a] 2.Qc7#[A] 1.Rg7? zz 1...Kd6[a] 2.Qc7#[A] 1...Kf6[c] 2.Qb2#[Б] but 1...Kd4/[б]/! 1.Qc1? (2.Qf4#) 1...Kd6[a] 2.Q