Correct answer: Qb71...Nd8[a]/Ne7[a]/Nb4+[a]/Nb8[a]/Na5[a]/Na7[a] 2.Nb4#[A] 1...Qe6/Qg5/Qh5/Qf4/Qg3/Qh2/[б]//Qg7 2.B:e6#[Б] 1...N:d4 2