Correct answer: Q:e61...e:f5/e5 2.Nd2# 1.Ra5[Б]? (2.Nd2#) 1...Be3[a] 2.Qe2#[A] 1...Bc5/[б]/ 2.Q:e6#[C] 1...B:c3 2.Qe2#[A]/Q:e6#[C]/Q:c3# but 1...b5!
