Correct answer: Bb21...Be7/B:f6[a] 2.N:b6#[A] 1...N:d6/[б]/ 2.Nc:d6#[Б] 1...R:c3 2.Nf2#/Ng3#/Ng5#/Nc5# 1.Be5?? (2.Nf2#/Ng3#/Ng5#/Nc3#/