Correct answer: Qc11...Kd3[a] 2.Bb1#[A] 1...Kd5 2.a8Q#/a8B# 1.g8Q? zz 1...Kd3[a] 2.Bb1#[A]/Qg6#/Qh7# 1...Kf5/[б]/ 2.Nge3#[C] 1...Kf3 2.