Correct answer: Qd51...B:e4+[a] 2.Q:e4#[A] 1...Ng1/Nh4/Ne1/[б]//Ne5/[б]//Nd4 2.Qf2#[Б] 1...Qh6/Qh7/Qh8/Qg6/Qf7/Qe8 2.N:g4# 1...Bd5/<
