Correct answer: Qd41...Nf4[a]/Ng1/Ng3/Nd4/Nc1 2.Re7#[A] 1...Nc8 2.b8N# 1.Q:f3? (2.Qf7#[Б]) 1...Nf4[a] 2.Re7#[A] 1...Nc8 2.b8N# but 1.