Correct answer: Qc61...Qc6[a] 2.R:c6#[A]/Q:c6#[Б] 1...Bd7 2.Ne7# 1...Qc3 2.Q:c3# 1.Rc6[A]? (2.Ne7#/R:b8#/Nd6#) 1...Q:c6[a] 2.Q:c6#[Б] 1...