Correct answer: N6:e51...Kd5[a] 2.R:e5#[A]/Nf6#[Б] 1...N:e3/f2 2.Nf6#[Б] 1...d:c5/d5 2.R:e5#[A] 1.Rf7? (2.Q:f3#[C]) 1...Kd5[a] 2.Nf6#[Б] but 1...d2! 1.d5? (2.<