Correct answer: Qe11...Rf3[a]/Bd1[a]/Bg6[a]/Bf7[c]/Be8[c]/Rg4[a] 2.Rd1#[A] 1...Bg4/[б]//Bf4[d] 2.B:e4#[Б] 1...Rg3/Bg1/Rf4 2.N:e5# 1...Re3/<
