Correct answer: Bf41...Qe7/Qe8/Qc6[a]/Qf7/Qg8/Qd5[a]/Qc4 2.Rf3#[A] 1...Q:b6/[б]/ 2.Rf4#[C] 1...Q:a2[c] 2.Rf2#[D] 1...Q:e5 2.Rf3#[A]/R:e5#[Б
