Correct answer: Bg31...Kf3[a] 2.Rgh2#[A] 1...K:d5/[б]//R:f5[c] 2.R:g4#[Б] 1...B:c1[d] 2.Rg3#[D] 1...Bh4/Bf4/Be3/Bd2/Bf6 2.Rg1#[C]/Rg3#[D]/R
