Correct answer: Bg21...N6c4[a] 2.Nb4#[A] 1...Na8/[б]/ 2.Ne3#[Б]/Nb4#[A] 1...Bg1 2.Q:e5# 1...d6 2.N:c3# 1.B:b6? (2.Ne3#[Б]/Nb4#[A]) 1...Bg1 2.Nb
