Correct answer: Q:e31...Nf2[a]/Ng3[a]/Ng5[a]/Nd2[a]/Nd6[a]/Nc3[a] 2.Rd4#[A] 1...Nh5/Nf5/Ne8 2.B:e6# 1.Nd7? (2.Nf4#[C]) 1...Nf2[a]/Ng3