Correct answer: c:d51...f3[a] 2.N:f3#[A] 1...d:c4/[б]/ 2.Qd7#[Б] 1.c:b5? zz 1...f3[a] 2.N:f3#[A] 1...e3[c] 2.d:e3#[C] but 1...B:b5! 1.Qe2? zz 1...f3[a] 2.Qe3#[D] 1...d:c4/[б]