Correct answer: Nd71...Qc3[a] 2.N:c3#[A] 1...Qa1/[б]//Qd2/Qb2/[б]//Nc6 2.N:c7#[Б] 1...Rg6/Bg8 2.Be4# 1...Qc4 2.b:c4# 1...Qb1/Qa3 2.Nc3#[A]/N<