Correct answer: Nd41...Nh4[a]/Nh8/Ne7[a] 2.g:f4#[A] 1...Bd5/Bc8/[б]//Ba6 2.R:d5#[Б] 1...f5[c] 2.Q:d6#[C] 1...Nf3/Ng2/Nd3[d]/Nc2 2.Nd3#[D] 1.R
