Correct answer: b71...c5[a] 2.Qe4#[Б] 1...b:c4/R:c4/[б]/ 2.Qe5#[A] 1...K:c4 2.Bb3# 1...d:e6/R:e6 2.Qd4# 1.Kf3? (2.Qe4#[Б]) 1...R:c4/[б]/ 2.Qe5#[A] 1...<
