Correct answer: Be51...Rc4[a] 2.Nf6#[A]/Re5# 1.Be3? (2.Qc6#) 1...Rc4[a]/R:g4 2.Q:e6#[D] 1...Kc4/[б]/ 2.Qb3#[Б] 1...Bc5[c] 2.Q:c5#[C] 1...R