Correct answer: Nd51...c3[a] 2.Bd5#[A] 1...d3/[б]/ 2.Qe3#[Б] 1.Nd3?? zz 1...c3[a] 2.Qe2#[C] 1...K:d3 2.Qc2# 1...Kd5 2.Q:d4# but 1...c:d3/[б]/! 1.B:c4?? (2.