Correct answer: Qc51...K:e5[a] 2.Qa1#[A] 1...Ng7/Nd6/[б]/ 2.Q:g7#[Б] 1...B:e5[c] 2.Qf7#[C] 1...Bg4/Bc2/Bb3/Ba4 2.N:g4# 1.Qa3? (2.Nd7#) 1