Correct answer: Nb31...K:e4[a]/b:c4[d] 2.Bc2#[A] 1...K:c4/[б]//f:e4[c] 2.Be2#[Б] 1.Ne6? zz 1...K:e4[a]/b:c4[d] 2.Nc5#[C] 1...K:c4/[б]/ 2.Ne5#[D] but 1...f:e4[c]! 1
