Correct answer: b8N1...Ke3[a] 2.Qa7#[A] 1.Qd8? zz 1...Ke3[a] 2.Qb6#[C] 1...Ke5/[б]/ 2.Qf6#[D] but 1...K:c4! 1.Kh7? zz 1...Ke3[a] 2.Qa7#[A] 1.
