Correct answer: Nd71...B:c3[a] 2.R:d6#[Б] 1...Re1/Re3/Re4/R:e5/Rd2/Rf2/Rg2/Rh2 2.Bc4#[A] 1.Nc6? (2.c4#) 1...B:c3[a] 2.Rb5#[D] 1...R<