Correct answer: Qd31...B:b4[a] 2.Qc7#[A] 1...d5/[б]/ 2.Qe7#[Б] 1.Qg8? (2.R:c4#/Q:c4#) 1...B:b4[a] 2.Qc8#[E] 1...d5/[б]/ 2.Qf8#[C] but 1...K:b4! 1.Qd3
