Correct answer: Qf21...Ke4[a]/Bf6[c] 2.Nd6#[A] 1...Ne4/[б]/ 2.Bd7#[Б] 1...Bg7[d] 2.N:g7#[C] 1...Nh3/Nh7/Nf3/Ne6 2.Bd3# 1...f3 2.R:e5# 1...Bd4/
