Correct answer: Qh51...Nc4[a] 2.Qd7#[A] 1...Bf2/Bg3/Bh4 2.R:b4# 1.Re5? (2.c6#) 1...Nc4[a] 2.Qd7#[A] 1...Nc6/[б]/ 2.Qd3#[Б] but 1...Bg3! 1.Q