Correct answer: Qg71...Kd5[a] 2.Qa8#/Qb7#[A] 1...f5 2.Qd4# 1.Ng7? zz 1...Kd5[a] 2.Bb7#[Б] 1...d5/[б]/ 2.Bf5#[C] but 1...f5! 1.Ng5+?? 1...Kd5[a] 2.B<