Correct answer: b41...Bf1/Bf3[a]/Bd3[a]/Bc4 2.Nf3#[A] 1...d5/[б]/ 2.Qf2#[Б] 1...Ne5/Nf6[c]/Nf8/Nc5[c]/Nb6/Nb8 2.Q:e5#[C] 1...f6 2.Ne6#
