Correct answer: Qd11.Q:e3? (2.Q:d3#) 1...Ne1[a]/Nf2[a]/Nf4[a]/Nc1[a]/Nb2[a]/Nb4[a] 2.R:c5#[A] 1...e4/[б]/ 2.Q:e4#[Б] 1...c4[c] 2.Rd7#[C] but 1...Kc4!
