Correct answer: Qg21...Kc3[a] 2.Q:d3#[A] 1...Rc3/[б]//d2[c] 2.Qe6#[Б] 1...Nd1/Na4 2.Qe6#[Б]/Q:d4# 1...R:c6+ 2.Q:c6# 1.Kb6? (2.R:c5#[C]) 1...Kc3
