Correct answer: Qg31...K:d4[a] 2.Qc4#[A] 1...N:d4/[б]//Nc4[c] 2.Nc5#[Б] 1...e:d4[d] 2.Qe6#[D] 1...Q:d4 2.Q:g2# 1...Nd3 2.Bc6#[C] 1.Qe6[D]? (2.Q:e5#)