Correct answer: Qb71...Ke4/B:c4[a] 2.Qg6#[A] 1...N:e3/[б]/ 2.Nf2#[Б] 1...N:c3[c] 2.N:c5#[C] 1.Qd6+?? 1...Ke4 2.Qd5#/Qg6#[A] but 1...K:c4! 1.Q<