Correct answer: Rd7+1...Ke3[a] 2.Q:c3#[A] 1...Ke5/[б]/ 2.Qc5#[Б] 1...Bf1 2.R:e4#[C] 1.Ne6+? 1...Ke3[a] 2.Q:c3#[A] 1...Ke5/[б]/ 2.R:e4#[C] 1...K