Correct answer: Be41...Nd5[a]/Ne6/[б]//Ne8[c]/N:b5[c]/Na6[c]/Na8[c] 2.N:d5#[Б] 1...B:d4[d] 2.Q:d4#[C] 1...d:c2[e] 2.Nce2#[E] 1...Ne5/Nf6/Nf8/Nb8 2
