Correct answer: Qd41...Ka3[a] 2.Qb3#[A] 1...Ka5/[б]/ 2.Qb5#[Б] 1.K:c7?? zz 1...Ka3[a] 2.Qb3#[A] but 1...Ka5/[б]/! 1.c3?? (2.Q:b4#) 1...Ka5/[б]/ 2.Qb5