Correct answer: Qa81...Qb6[a] 2.Rcb4#[Б] 1...Qc5/[б]/ 2.Q:c5#[D]/Qa6#[A] 1...Kb6/Qc7 2.Qa6#[A] 1...Qd5 2.Qa6#[A]/Rcb4#[Б] 1...Qd4/Qe7 2.Qc6#[C]/
