Correct answer: Ke21...Kc1[a] 2.Qc2#[A] 1...R:a2/[б]/ 2.Qd1#[Б] 1...Bb4/Bc5/Bd6/Be7/Bf8 2.Q:b2#[C] 1.Kc3[D]? zz 1...Kc1[a] 2.Qc2#[A] 1...