Correct answer: Qh41...Bg5[a]/Bh6/[б]//B:e3[c] 2.Q:g3#[A] 1...g2[d] 2.Q:g2# 1...d:e2 2.K:e2# 1.Q:f4? (2.O-O-O#/Q:g3#[A]) 1...g2[d] 2.O-O-O# 1...g:f2+ 2.Q:f2# 1...d
