Correct answer: Be21...Rc1[a]/Rd1/[б]//Re1[c] 2.Q:b2#[A] 1...Bc3[d]/Bd4[e]/Be5[f]/B:f6[g] 2.Ra2#[Б] 1...R:f1+ 2.R:f1# 1.K:f4? zz 1...Rc1[a]/R<